We present four solutions from Informator #113 with thanks to Josip Asik.
A Morozevich- L van Wely (W)
Pamplona, 1998
1 h4!+- Ke7 (1…Qxc3 2 Qf3 Qxf3 3 gxf3 d4 4 Kg2) 2 h5 Qxc3 3 h6 e4 4 Qg7! Qe3 (4…Qc7 5 Qg3) 5 Qe5+ Kd7 6 Qxd5+ Ke7 7 Qe5+ Kd7 8 Qf6 1-0.
A Morozevich-O Korneev (W)
Pamplona, 2006
1 Rxa6+ Kb8 2 Qf4+ Rd6 (2…Rd6 3 Qxd6+ Qxd6 4 Rxd6 c2 5 Rf1 Be4 and White is slightly better) 3 Rxb7+ (3 Rxd6 c2) 3…Kxb7 4 Rxd6 Qxb3 5 Qf7+ 1–0
V Milov-A Morozevich (B)
Pamplona, 2006
1…Ra7! 2 Be4 ~ only move ~ 2…f5 0-1.
M Adams-A Morozevich (B)
Dortmund, 2001
1…Rf4! 2 Qe3 (2 Qxf4 Bxf4 3 Bc8 Qh4+ 4 Kg1 Qh2 {4…Bh2+ 5 Kf1 Qc4 6 Re2 Qxc8-+} 5 Kf1 Bc4+ -+) 2…Rh4+ 0-1
The positions are in BCM August, 2012 issue, p.416.
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What are the starting positions?
J.
we don’t give the positions to preserve a little mystery. However, if you can’t wait for the 08/12 issue (and why should you?) we refer all interested parties to ‘Informator No. 113′ – our source – and the fantastic Alexander Morozevich retrospective. It rocks!
James